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某住宅小区工程临时用电施工方案(含电子图)P=1.05~1.10(K1∑P1/cosφ+K2∑P2+K3∑P3+K4∑P4)式中;
K1=0.6 K2=1 K3=0.8K4=0.8
(1)动力设备的总功率为:
聚苯颗粒外墙保温施工方案∑P1=1683.6KW(K1取0.6)
(2)办公区、生活区总功率为
∑P2=100KW(K2取1)
(3)室外照明总功率为:
∑P3=35KW(K3取0.8)
(4)其他(食堂)总功率为:
∑P4=150KW(K4取0.8)
因此施工总用量为:(cosφ=0.75)
P=1.05(K1∑P1/cosφ+K2∑P(2+K3∑P3+K4∑P4)
=1.05(0.6×1683.6/0.75+1×100+0.8×35+0.8×150)=1674.63KVA
业主现场提供3台630KVA变压器,1890KVA>1674.63KVA,可满足施工要求。
四、主要供电回路电缆截面的计算与选择
2、箱变至总配电箱线路计算及电缆选择
(1)变压器I至总配电箱ZP1电缆选择
P=26+33+29.6+126.8=215.4KW
I=KxP/1.732UCOSφ
=0.6×215.4/1.732×380×0.75
(2)变压器I至总配电箱ZP2电缆选择
P=26+33+29.6+80+110=278.6KW
I=KxP/1.732UCOSφ
=0.7×278.6/1.732×380×0.75
(3)变压器I至总配电箱ZP3电缆选择
P=52+66+59.2=177.2KW
I=KxP/1.732UCOSφ
=0.6×177.2/1.732×380×0.75
(4)变压器III至总配电箱ZP4电缆选择
P=26+33+29.6+100+110=298.6KW
I=KxP/1.732UCOSφ
=0.7×298.6/1.732×380×0.75
(5)变压器II至总配电箱ZP5电缆选择
P=26+33+29.6+126.8=215.4KW
I=KxP/1.732UCOSφ
=0.6×215.4/1.732×380×0.75
(6)变压器II至总配电箱ZP3电缆选择
P=52+66+59.2=177.2KW
I=KxP/1.732UCOSφ
=0.6×177.2/1.732×380×0.75
(7)变压器III至总配电箱ZP7电缆选择
P=26+33+29.6+126.8=215.4KW
I=KxP/1.732UCOSφ
=0.6×275.4/1.732×380×0.75
3、总箱至二级配电箱线路计算及电缆选择
I=P/(√3×U线×cosφ)
=26/(1.732×380×0.75)
I=P/(√3×U线×cosφ)
=33/(1.732×380×0.75)
I=P/(√3×U线×cosφ)
=29.6/(1.732×380×0.75)
I=P/(√3×U线×cosφ)
=63.4/(1.732×380×0.75)
I=P/(√3×U线×cosφ)
=110/(1.732×380×0.75)
I=P/(√3×U线×cosφ)
=80/(1.732×380×1)
I=P/(√3×U线×cosφ)
=100/(1.732×380×1)
4、主要设备开关箱的电缆选用:
(1)钢筋切断机线路计算:(取cosφ=0.75)
I=P/(√3×U×cosφ)
=4.5/(√3×380×0.75)
(2)钢筋弯曲机线路计算:(取cosφ=0.75)
xxx洁净污水处理厂配套截污主干管工程施工组织设计I=P/(√3×U×cosφ)
=3/(√3×380×0.75)
(3)交流电焊机线路计算:(取cosφ=0.75)
I=P/(√3×U×cosφ)
=23.4/(√3×380×0.75)
(4)钢筋调直机线路计算:(取cosφ=0.75)
I=P/(√3×U×cosφ)
GB/T 51316-2018标准下载=4.5/(√3×380×0.75)